A partir das equaçőes :
H2( g)+1/2O2( g)→H2O(l)ΔH=−68,3kcal/molH2( g)+1/2O2( g)→H2O(v)ΔH=−57,8kcal/mol
A variação de entalpia para o processo H2O(v)→H2O(1) é:
a. +126,1kcal/mol e o processo é endotérmico.
b. −10,5kcal/mol e o processo é endotérmico.
c. −10,5kcal/mol e o processo é exotérmico.
d. −126,1kcal/mol e o processo é exotérmico.
e. +10,5kcal/mol e o processo é endotérmico.
![A partir das equaçőes :
\[
\begin{array}{l}
\left.\mathrm{H}_{2}(\mathrm{~g})+1 / 2 \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{H}_{2} \mathrm{O}_{(\mathrm{l}}\right) \Delta \mathrm{H}=-68,3 \mathrm{kcal} / \mathrm{mol} \\
\mathrm{H}_{2}(\mathrm{~g})+1 / 2 \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{v}) \Delta \mathrm{H}=-57,8 \mathrm{kcal} / \mathrm{mol}
\end{array}
\]
A variação de entalpia para o processo \( \mathrm{H}_{2} \mathrm{O}(v) \rightarrow \mathrm{H}_{2} \mathrm{O}(1) \) é:
a. \( +126,1 \mathrm{kcal} / \mathrm{mol} \) e o processo é endotérmico.
b. \( -10,5 \mathrm{kcal} / \mathrm{mol} \) e o processo é endotérmico.
c. \( -10,5 \mathrm{kcal} / \mathrm{mol} \) e o processo é exotérmico.
d. \( -126,1 \mathrm{kcal} / \mathrm{mol} \) e o processo é exotérmico.
e. \( +10,5 \mathrm{kcal} / \mathrm{mol} \) e o processo é endotérmico.](https://prod-meuguru-guruia-assets.s3.sa-east-1.amazonaws.com/A-partir-das-FKTvPHPbT?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Content-Sha256=UNSIGNED-PAYLOAD&X-Amz-Credential=ASIAQXTC4KK6Z67ZS42H%2F20250428%2Fsa-east-1%2Fs3%2Faws4_request&X-Amz-Date=20250428T053509Z&X-Amz-Expires=900&X-Amz-Security-Token=IQoJb3JpZ2luX2VjENL%2F%2F%2F%2F%2F%2F%2F%2F%2F%2FwEaCXNhLWVhc3QtMSJHMEUCIDC50vCelEe5%2F%2FVa7TFzrofx2efTpck%2FP1z7QjEjGmsPAiEA%2FPZupLuDPhqBgD21RrmUjyNarSVoUG2XdidzryUbUGIq5QMIaxACGgwwNTA2NzMyNDI4MTMiDIYAL9irjyZCcYnNcCrCA3DfwtgahGtowncUZLKpY8iBB8VxdubxyCLlHjDFD8zh%2B6ONa0Qgj1MG18tsLIqvM8ANMIs1MeZaGYToRoVPwX1ZAfbxUPojhVeRoiZHXs26rXgb%2BZ2xwgMG5fiTuzH8GBWDY9vmQIS%2FrrFKEmydhga16uHcmTN4DsaZPT7VftDvROZ6UR0IYqPGGrueSK%2FgdsxXNo8KbI2MaknWm83BD2nAFB2xEStFkj4mfGoML4P0drLkOuZcj%2B1H30H6nskZo%2BAFie%2FMBWEojlfaPTdJ1sL%2BLEsghRcYANBc4Cj4BfsBAuIY4EyOSsfimvW058fl1GyMw68slCoj6kym18cTLb89yGMWfKnux%2F8CJAxGertd3o6KBzqriK7sbqeYxvrrfVp50g%2BXa0Zf0jZgYii7B6ERfuB6vM%2F5zMFQpwDNT7f%2BLJrCW3FEHIPF8P5U4WLiEBqomONm%2BYa1dZJKQjEXXexNixLX1SCjqv4Y%2FXgOHzsB5mZ3r2oeMF%2Bl18bvhqQM3qHknpGcBc%2BnhifytinNaCt0qAOFAkAE40A7EbGr2eKupaFg66TrcEUrWdiPE2G332ddfjwltEPb8loqDxuW25abTDDetbvABjqlAfGnuoDQSlhyzSdKEuDZ2T0JfArrSO4g1qhooRCY8ncq270u82NQCRSsPnkWq31%2B6Aa7VyDV2JBYyxJD%2FVDH999dSfmUyNciHGWR9h3DC8n8DplCgOxMCKhvR2shjt3A9bxrNmjXYuFuL3j5AnXBt762XzqujVMVSgceed1AQ4prnpcRLaYMCsKFu033Jb3y2rhefsubhAe1wHCvsy0w2b5dmvwT9A%3D%3D&X-Amz-Signature=f441d47fc7266a6eb312055a1db49f07d454e8d5b65d044e21508e9bf7a450d7&X-Amz-SignedHeaders=host&x-id=GetObject)
