Sm1 40thru1 41

PROBLEM 1.40\n\nPout = 14.5 psia\n\nPin = 5.5 psig\n\nFrom the compressor pressure ratio, the exit pressure can be determined from \n\npressure ratio = Pexit/Pin -> Pexit = Pin (pressure ratio)\n\nInlet pressure must be expressed as absolute pressure to solve for exit pressure. Conversion from the inlet pressure gage reading to absolute pressure is determined from\n\nPin(gage) = Pin(absolute) - Patm(absolute)\n\nRearranging the equation to solve for Pin(absolute) and substituting values yield\n\nPin(absolute) = Pin(gage) + Patm(absolute) = 5.5 psig + 14.5 psia = 20 psia\n\nSubstituting absolute pressure at the inlet into the equation for exit pressure yields\n\nPexit = (20 psia)(8) = 160 psia\n\nPROBLEM 1.41\n\nPiston\nPiston\nP1 = 14.7 lbf/in2\nPatm = 100 in-H2O\nP2 = 11 Ft2\n\n= 3 32.0 lbf/ \n\nTwall = \n\nP1=\n\nFig. P1.41\n\nWith Eq. 1.41 we get,\n\nP1 = 0.6 lbf/in2 (gage).