Lista de Quantidade de Materia

Ca = 40.078 \quad \quad \quad \quad Al = 26.985 x 2 \\ O = 15.998x2 \ \quad 53.92-20658.3 \\ H = 1.008 \\ \ \ c) Ca(OH)_2 \ \ 74.092 g/mol \\ x = 105 \quad \quad x=20 \\ \\ 74.082 \quad \quad \quad 342.14 \\ \ \x=1.417 \text{ moles} \quad x=0.087 \text{ moles} \\ \\ e) HNO_3 \ \ H=1.008 \\ N=14.007 \quad \quad O_3=15.994 x 3 \\ \x=398 \\ 63.012 \\ x=2.999 \text{ moles} \\ \\ \ \ NaOH \quad \quad \quad \ Na=22.99 \\ O=15.994 \quad H=1.008 \\ \ \ \x=4.0 \\ 39.997 \\ 32.23 \rightarrow x \\ \\ 41g \\ 210 mg = 0.21 g \\ \left( \frac{1}{1000} \right) \rightarrow 2.71 x 10^{-1} \\ \ \ NaHCO_3 \ \ 1 = 1 \ \ \ \ 76 = 76 g/mol \\ C = 12 \\ \ \ \ O_3 = 16 \times 3 = 48 \\ x = 1 \text{ mol} \ \ 84 \\ \ \frac{6.02 \times 10^23}{84} \\ \ \frac{x}{2.1 \times 10} \\ 84x = 12.6 \times 10^{24} \\ x = 12.6 \times 10^{24} \\ x=0.15 \times 10^{22} \\ \x=1.5 \times 10^{21} \\ \ \5) 298 = 32 \times 10^{-1} \\n6.02 \times 10^{23} \\ x=6.02 \times 10^{23} \times 2.8 \times 10 \\ \left( 5.6 \times 10^{7} \right) \\ x=3:01 \times 10^{23} \text{ átomos} b) \frac{6.02 \times 10^{23}}{x} = \frac{44g}{88g} \\ 44x = 528.96 \times 10^{23} \\ x = \frac{528.96 \times 10^{23}}{44} = 12.04 \times 10^{23} \text{ atoms} \\ \\ 6) \frac{6.02 \times 10^{23}}{x} = \frac{197g}{985g} \\ x = 6.02 \times 10^{23} \times \frac{985}{197} \rightarrow 3.0 \times 10^{22} \text{ atoms} \\ \\ 7) \\ CO_2 = C = 12 \quad 44 \text{ toneglass} \\ O_2 = 16 \times 2 \quad 58 \times 10^6 g \\ = 44 g = \frac{6.02 \times 10^{23}}{58 \times 10^6} \\ \frac{6.02 \times 10^{23}}{x} \\ \\ 44x = 58 \times 10^6 \times 6.0 \times 10^{23} \\ x = \frac{5.28 \times 10^{31}}{44} = 1.2 \times 10^{30} \text{ toneglass} \\ \text{molecules} \quad \text{atoms} \\ 1 \quad \quad \quad \quad 3 \\ 1.2 \times 10^{30} = y \\ \\ y = 1.2 \times 10^{30} \times 3 \\ \ y = 3.6 \times 10^{30} \text{ atoms} 8) \frac{18g}{x} = \frac{6.02 \times 10^{23}}{7.2 \times 10^{23}} \\ \\ x = \frac{7.2 \times 10^{23} \times 18}{6.0 \times 10^{23}} = 1.296 \times 10^{25} = 216 g \\ \\ 9) \quad \text{molecules} \\ a) 1 \text{ mol} = 6.0 \times 10^{23} \\ 5 \text{ mol} = x \\ x = 5 \times 6.0 \times 10^{23} \\ x = 3 \times 10^{24} \text{ molecules} \\ b) 1 \text{ mol} = 98 g \\ \frac{x}{490g} \rightarrow 5 \text{ mol} \\ \\ \text{N° Átomos} \\ \n3.10^x \rightarrow 2.1 \times 10^{25} \text{ átomos} \\ \text{A molécula de H}_2\text{SO}_4 \text{ tem 7 átomos} \text{...} \\ \text{MULTIPLICA N° de moléculas por 7.} \\ \\ 10) \frac{1 \text{ mol} \text{ C}_8\text{H}_8}{\text{molecules}} = \fraction{6.0 \times 10^{23}}{x} \\ \fraction{20}{x} \\ x = 20 \times 6.0 \times 10^{23} \\ x = 1.2 \times 10^{25} \\ \\ \frac{1 \text{ mol} \text{ C}_8\text{H}_8}{\text{atoms}} = \frac{x}{11 \times 6.0 \times 10^{23}} \\ 20 \rightarrow \text{3} \\ \x = 20 \times 11 \times 6.0 \times 10^x \\ \nx = 4.32 \times 10^{25} \text{ átomos}