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Ejercicio N° 50\n1 calculo Kab\nK'12 = 3/2 EJ1 / 3m = 1/2 EJ1\nK23 = -2 EJ2 / 4m = -2 EJ1\nK35 = 2EJ1 / 1m = 1/2 (1,5 EJ1) = 3 EJ1 / 4\n2 calculo Mab ( tablas )\nM = q - 2tm\nM e 23 = - q/2 - 9/8 = - 3/8\nM e 32 = q/12 = 8/3\n3 Ecuc. Nudo 2\nM21 + M e 23 + 2 (Φ2 (K12 + K23) + Φ3 K23 + 2 (Φ12 K12) = 0\nEcuc. Nudo 3 \nM e 32 + M e 35 + 2 (Φ2 (K29 + K35) + Φ3 K23 + 3 (Φ) K35 = 1\nEcuc. de P150\nΣ Ph + Σ P = (M e 21 + M e 35 + M e 53) / 2 + 3 (Φ1 + 2 (Φ12 K12)\n+ 6 (Φ35 - K35) + 2 (Φ12 K12) = 0\n1. - 3/8 - 2 Φ2 (1/2 + 2) + Φ3 (2) + 2 Φ12 (1/2) = 0\n2. 8/3 + (-1/2) + 2 Φ3 (2 + 5/4) + Φ2 (2) + 3 Φ35(3/4) = 1\n3 - 2 + ( 1/3 - 1/2 ) + ( 8/3 = 0\n+ 3 Φ3 3/4 + 2 Φ12 1/2 = 0\nΦ12 x 3m = Φ35 x 4m → Φ12 = 4/3 Φ35 5 (Φ2) + 2 (Φ3) + Φ12 = 61/24\n2 (Φ2) + 5,5 (Φ3) + 27/16 (Φ12) = - 7/6\n1/3 (Φ2) + 9/16 (Φ3) + 113/9 (Φ12) = - 1.875\nou\n5 (Φ2) + 2 (Φ3) + 4/3 (Φ35) = 61/24\n2 (Φ2) + 5.5 (Φ3) + 9/4 (Φ35) = - 7/6\n1/3 (Φ2) + 9/16 (Φ3) + 113/7 (Φ35) = - 1.875\nΦ2 = 0.86 [rad] → E1 \nΦ3 = 0.045 [rad] → E1 \nΨ12 = -1.86 [rad] → E1\nΨ35 = 3/4 Ψ12 M21 = -0.87 tm\nM22 = 0.84 tm\nM32 = 4.57 tm\nM35 = -3.57 tm\nM53 = -2.60 tm\n2.64 0.87\n2t/m 4.57\n2.64\n0.04\n1t\n0.04\n0.14\n3t\nQ21 = 1/3 - 0.84/3 = 0.04t ( → ) \nQ35 = -1 + (-3.57 - 2.60)/4 = -2.04t ( ← ) 2t\n\nQ21\n\nQ35\n\nM21\n\nM12\n\nP150\n\nM21 = 0\n\nΣ Qsi\n\nΣ Ph + Σ A + Σ Mi + MS = 0\n\n2 + (1/3 - 1/2) + M21/3m + M35 + M53/4 = 0\n\nVerif.\n{ M21 + M23 = 0 (Ec. Nudo 2)\nM32 + M35 = 1 (Ec. Nudo 3) \nΣ Ph + Σ A + M21/3 + M35 + M53/4 = 0 (Ec. Desplazm. Piso)