Lista Difração - Resolvida física 3-d

1)\nFisica 1D - Lista Difraccion\n\\Delta = 2.441 = 0.117mm\n\ng = z m \\lambda\n\\theta = 15.10° \\rightarrow \\theta = 0.43°\n\n3)\n\\lambda_{G1} = 1.550\n\\lambda_{G2} = 5.550\n\n\\mathit{g}(\\theta_{G2}-\\theta_{G1}) \\approx \\frac{350\\cdot 10^{-6}}{g} \\sin 9.74\\cdot 10^{-6}\n\n\\frac{\\lambda_{G2} - \\lambda_{G1}}{a} = 2.351\\cdot 10^{-5} m\n\n5)\nf: 3000Hz\nn1 = 343\nl2 = 343/3000\\cdot c_{1.1} m\n\\lambda = 11.4cm\n\n6)\nl = 632.8nm\n1.437\\cdot 10^{-8} = 10.6328nm\n\\theta = \\frac{633.9\\cdot 10^{-9}}{1.437\\cdot 10^{-8}} = 61.9\\cdot 10^{-6} rad\n\ny = \\frac{1}{2}y\n\\lambda = 12mm\n\n7)\n0.10mm\n0.10mm\n\\lambda= 0.1103nm\\cdot 30° = nm5.580\\cdot 10^{-7}\n\nm = 5.0\\cdot 10^{-6} = 6.143\\cdot 10^{-6} \n\\theta = 2.35610-3 \\rightarrow \\lambda = 2{7}° = 360°\n 8)\n\\theta_{0} = 1.41\\cdot 10^{-10} rad = (11.10°)\n\\alpha = 1°\n\\lambda = 1.5\\cdot 10^{-10} = 5.5\\cdot 10^{-3}nm\n\nI(\\theta) = I_{max} (cos^2(\\frac{(\\theta + \\theta_{0})}{2}))\n\n\\sum(0.10°)² = 2\\cdot \\sum I_{nm}(\\lambda)\\rightarrow K = 0.991\n\n9)\n\\lambda = 1.22\\cdot 550.10^{-6} = 1.342\\cdot 10^{-6}\n\\theta = 0.7\\cdot \\lambda\\rightarrow x = 10.4\\cdot 10^{-6} \\rightarrow x = 10.4km\n\n10)\n\\lambda_{R1} = 1.22\\cdot 550.3 = 1.22\\cdot 1.3 = 10.4\\cdot 10^{-6}\n\\lambda_{R2} = 1.22\\cdot 12.5\\cdot 10^{-6}\n\n\\lambda = 10 m = 10^{-9}\n\\lambda = \\frac{d}{d'} \\rightarrow d = 3.5\\cdot 10^{-6}m\n\n11)\n\\lambda = 0.1mm\n\\theta = \\frac{m}{d}\n\\theta_{0} = \\frac{\\lambda}{d} = \\frac{550.10^{-9}}{3.53\\cdot 10^{-6}}\n 12)\n\\lambda = 1.65nm\\rightarrow d_{Z} = 2mm\n\\lambda = 16.6nm\n\n13)\n\\lambda = 4350m\n\\omega = 1.22m\n\\theta_{m0} = 1.22 + 5.6212 \\rightarrow 60.10°\n\\theta = 6.70°\n\n14)\nD = dN\n\\frac{d}{d} = 3.353 m\n\n15)\nD = 10 m\nN = 10,000 = 10^{-6} = \\lambda = 0.5m\n\n19)\n\\lambda_{max} = 0.2 = m600.10^{-6}\n\\lambda_{max} = 1 - \\lambda_0 \n\n\\lambda_{max} = 0.3 - 0.3m = 0.33mm = 600.10^{-6}\n 21)\nλ medio= 683.3 nm\nΔλ = Δm/m \nR = Δλ = N·nm\nΔλ = 500·10−9 N·nm\nN = 3 656.3 = 3646.1\n\n22)\nD = N·cl\nN = 415.5 \n− 28,100 nm/nm² \n0.0092\n\ncl= 4×10^−12/ 1.74×10^−6\n\nR = Δm = N·nm/m\n\nN = 415.5·\n\n23)\nN = 94.0·10^−9\nλ = 76·10−6\n100 m = 0.39 nm\nλ = 583 nm\nD = m2 + D = \nm + D= \n\n1.9 μm\n\n24)\n2d sin θ = mλ\n\nm = 1,2\n\nλ = 30·10^−12 = mθ\n2·0.9·10^−6\n\n25) 2d sin θ = mλ\n\nλ = 2d·θ/m\n\nλ = 2.39·8·10^−12·10^30° = 39.8 pm\n\n26)\nλ = 0.5pm\nΔλ = 19 nm\n\nd = 29 pm\nθ: 90-45 = 45°